Solution -
90
First add two digit the multiple in 3rd digit=Answer
3+2+5=25====3+2=5x5=25,
4+1+9=45 =====4+1=4x9=45
then 8+7+6======8+7=15x6=90
90
First add two digit the multiple in 3rd digit=Answer
3+2+5=25====3+2=5x5=25,
4+1+9=45 =====4+1=4x9=45
then 8+7+6======8+7=15x6=90
7+1=7^2+1^2=49+1=50
Logic-- x^2+y^2=z
Such as 6+2=40
6^2+2^2=40
4+3=25
4^2+3^2=25
And so on .
Solve the popular algebraic equation by replacing alphabets with a digit and equation must be true as well?
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9 - 1 = 8
17 - 9 = 8
33 - 17 = 16
49 - 33 = 16
73 - 49 = 24
X - 73 = 24
X = 73 + 24 = 97
If,
a + a = 10
a + @ = 15
a + e = 25
Then;
a + @ + e = ??
Given,
a + a = 10
i.e.
2a = 10,
so a = 5.......................................(i)
a + @ = 15,
@ = 15 - a, but a = 5,
so @ = 10....................................(ii)
a + e = 25,
e = 25 - a, but a = 5,
so, e = 20.....................................(iii)
adding the three equations above, we have
a + @ + e = 5 + 10 + 20
which gives,
a + @ + e = 35
5, 39, 8, 9, 40, 11, 13, 27, 14, 15, ......, 17
(5, 39, 8), (9, 40, 11), (13, 27, 14), (15, ......, 17)
a b c
b = c^2 - a^2
8^2-5^2 = 64-25 = 39
11^2-9^2 = 121-81 = 40
14^2-13^2 = 196-169 = 27
Similarly
17^2-15^2 = 289-225 = 64
36-31=5
31-29=2
29-24=5
24-22=2
22-17=5
17-15=2
15-x=5 ,..... 15-5=x
so x =10
36 - 5 = 31
31 - 2 = 29
29 - 5 = 24
24 - 2 = 22
22 - 5 = 17
17 - 2 = 15
15 - 5 = 10.