If, a + a = 10; a + @ = 15; a + e = 25 Then; a + @ + e = ??

If,

a + a = 10

a + @ = 15

a + e = 25

Then;

a + @ + e = ??

Solution -

Given,
a + a = 10
i.e.
2a = 10,
so a = 5.......................................(i)

a + @ = 15,
@ = 15 - a, but a = 5,
so @ = 10....................................(ii)

a + e = 25,
e = 25 - a, but a = 5,
so, e = 20.....................................(iii)

adding the three equations above, we have

a + @ + e = 5 + 10 + 20
which gives,

a + @ + e = 35